PHP/Language Basics/Variable Reference — различия между версиями
Admin (обсуждение | вклад) м (1 версия) |
Admin (обсуждение | вклад) м (1 версия) |
(нет различий)
|
Текущая версия на 07:05, 26 мая 2010
Содержание
- 1 $b is assigned a copy of $a, and in the second part, $b is assigned a reference to $a.
- 2 Create a reference to a variable with the name of the constant"s value.
- 3 Only named variables may be assigned by reference.
- 4 & operator creates a reference
- 5 Passing arrays by reference
- 6 Passing by Reference in PHP
$b is assigned a copy of $a, and in the second part, $b is assigned a reference to $a.
<?php
$a = 5;
$b = $a;
$a = 7;
echo "\$a = $a and \$b = $b\n";
$a = 5;
$b = &$a;
$a = 7;
echo "\$a = $a and \$b = $b\n";
?>
Create a reference to a variable with the name of the constant"s value.
<?php
define("CONST_A", "test");
${CONST_A} = 27;
echo "\$test = $test\n";
?>
Only named variables may be assigned by reference.
<?php
$foo = 25;
$bar = &$foo; // This is a valid assignment.
function test() {
return 25;
}
$bar = &test(); // Invalid.
?>
& operator creates a reference
<?php
$a = 5;
$b = $a;
$a = 7;
echo "\$a = $a and \$b = $b\n";
$a = 5;
$b = &$a;
$a = 7;
echo "\$a = $a and \$b = $b\n";
?>
Passing arrays by reference
<?
function load_member_data($ID, &$member) {
$member["Name"] = "Bob";
return true;
}
$ID = 1;
$result = load_member_data($ID, $member);
if ($result) {
print "Member {$member["Name"]} loaded successfully.\n";
} else {
print "Failed to load member #$ID.\n";
}
?>
Passing by Reference in PHP
<?php
function reference_test($var, &$result, &$result2) {
$result = "This is return value #1";
$result2 = "You entered $var as your parameter";
return 42;
}
$res = reference_test(10, &$res1, &$res2);
echo "The value of \$res is "$res"<BR>";
echo "The value of \$res1 is "$res1"<BR>";
echo "The value of \$res2 is "$res2"<BR>";
?>