XML/XSLT stylesheet/format date
Версия от 18:22, 25 мая 2010; (обсуждение)
December in German
File: Data.xml
File: Transform.xslt
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:text>December 25, 1960 in German: </xsl:text>
<xsl:value-of select="format-date(xs:date("1960-12-25"), "[D] [MNn,3-3] [Y0001]", "de", "AD", "DE")"/>
</xsl:template>
</xsl:stylesheet>
Output:
December 25, 1960 in German: 25 Dez 1960
format-date(/orgchart/@date, "[D1] [MNn] [Y1]")
File: Data.xml
<?xml version="1.0"?>
<orgchart date="2004-03-31">
</orgchart>
File: Transform.xslt
<?xml version="1.0"?>
<html xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xsl:version="2.0">
<head>
<title>Management Structure</title>
</head>
<body>
<p>
<xsl:value-of
select="format-date(/orgchart/@date, "[D1] [MNn] [Y1]")" />
</p>
</body>
</html>
Output:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Management Structure</title>
</head>
<body>
<p>31 March 2004</p>
</body>
</html>
select="format-date(current-date(),"[dwo]")"
File: Data.xml
File: Transform.xslt
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:text>
 Today is the </xsl:text>
<xsl:value-of select="format-date(current-date(),"[dwo]")"/>
<xsl:text> day of the year. </xsl:text>
</xsl:template>
</xsl:stylesheet>
Output:
Today is the three hundred and forty-fifth day of the year.