PHP/MySQL Database/Database Update

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Версия от 07:06, 26 мая 2010; Admin (обсуждение | вклад) (1 версия)
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Get affected rows for an update

<?php
   mysql_connect("mysql153.secureserver.net","wbex","password");
   mysql_select_db("wbex");
   $query = "UPDATE Employee SET salary = "39.99" ";
   $result = mysql_query($query);
   echo "There were ".mysql_affected_rows()." product(s) affected. ";
?>



Update data record and get the affected rows

<html>
  <body>
  <?php
  $host="mysql153.secureserver.net";
  $uname="wbex";
  $pass="password";
  $database="wbex";
  $tablename="Employee";
  
  $connection= mysql_connect($host,$uname,$pass)  or die("Database connection failed!<br>");
  $result=mysql_select_db($database) or die("Database could not be selected");
  $query = "UPDATE Employee SET Firstname=\"new Name\" where id=2";
  $result = mysql_query($query);
  if (!$result) {
     die(" Query could not be executed.<br>");
  } else {
  echo "<table> ";
  echo " <tr>";
  echo "   <td colspan=\"2\">";
  echo "     <center><b>".mysql_affected_rows()." record updated successfully</b></center>";
  echo "   </td>";
  echo "  </tr>";
  echo "  <tr>";
  echo "    <td>";
  echo "      <div align=\"right\"> Name</div>";
  echo "   </td>";
  echo "   <td>".$name. "</td>";
  echo " </tr>";
  echo " <tr>";
  echo "   <td>";
  echo "     <div align=\"right\">E-mail</div>";
  echo "    </td>";
  echo "    <td>".$email. "</td>";
  echo "  </tr>";
  echo "  <tr>";
  echo "    <td>";
  echo "      <div align=\"right\"> CustomerID</div>";
  echo "    </td>";
  echo "    <td>".$customerid. "</td>";
  echo "  </tr>";
  echo "</table>";
  }
  ?>
  </body>
  </html>



Update Employee table

<?php
   mysql_connect("mysql153.secureserver.net","wbex","password");
   mysql_select_db("wbex");
   $rowID = "0001";
   $name = "Kate";
   $price = "12";
      $query = "UPDATE Employee SET name="$name", price="$price" WHERE ID="$rowID"";
      $result = mysql_query($query);
      if ($result) 
         echo "<p>The developer has been successfully updated.</p>";
      else 
         echo "<p>There was a problem updating the developer.</p>";

?>